Форум АНТИЧАТ - Что не так?

Ругается:
Parse error: syntax error, unexpected '{' in Z:\home\test1.ru\www\php\co\admin.php on line 17

Что не так?

Код:

<?

include("db.php");

if (isset($_POST['login']))

{

if (strlen($_POST['login']) > 4)

{

$login = htmlspecialchars(mysql_escape_string($_POST['login']));

$password = htmlspecialchars(mysql_escape_string($_POST['password']));

$result = mysql_query("SELECT login,password FROM admin WHERE login='$login'");

$result = mysql_fetch_array($result);

if ($result['password'] == $password) 

{

$session = md5($login."sdsdsadasdsadas");

setcookie("SESSION",$session); 

$ip = getenv("REMOTE_ADDR"); 

mysql_query("INSERT INTO admin (session,ip) VALUES ('$session','$ip') WHERE login='$login'"); 

} esle {echo("Пароль не верен!");}

} esle {echo("Логин кароткий!");}

} esle {echo("404 Not Found");}

if (strlen($_COOKIE['SESSION']) = 32) 

{

$session = htmlspecialchars(mysql_escape_string($_COOKIE['SESSION']));

$result = mysql_query("SELECT session,ip FROM admin WHERE session='$session'");

$result = mysql_fetch_array($result);

$ip = getenv("REMOTE_ADDR");

if ($result['session'] == $session)

{

if ($result['ip'] == $ip)

{

echo("123123");

} 

esle 

{

 mysql_query("UPDATE admin SET session=" WHERE session='$session');

echo("404 Not Found"); 

}

} esle {echo("404 Not Found");}

} esle {echo("404 Not Found");}

?>



<form method="post" action="" onSubmit="return CheckForm(this);">

<input name="login"  size="20" value="" style="width: 403px" ></br>

<input name="password"  size="20" value="" style="width: 403px" ></br>

<input type="Submit"  value="ОК" style="margin-top:4px; width: 61px;"></form>