16.06.2009, 18:51
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Постоянный
Регистрация: 03.06.2009
Сообщений: 385
Провел на форуме:
3178262
Репутация:
389
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Думаю вы хотели как-то так
PHP код:
<form id="form" name="form" method="post" action="?">
<select id="type_1" name="type_1">
<option value="0" selected="selected">Выберите счет:</option>
<option value="1">Касса</option>
</select>
<select id="number_1" name="number_1">
<option value="0" selected="selected">0</option>
<option value="1">1</option>
<option value="2">2</option>
</select>
<br>
<select id="type_2" name="type_2">
<option value="0" selected="selected">Выберите счет:</option>
<option value="1">Касса</option>
</select>
<select id="number_2" name="number_2">
<option value="0" selected="selected">0</option>
<option value="1">1</option>
<option value="2">2</option>
</select>
<br>
<input type="submit" value="Отправить">
</form>
<?php
class Bill
{
var $number;
var $type;
var $number1;
var $type1;
var $typeofinformation;
function display()
{
echo('Дебет: ' . $this->number . '<br>');
echo('Кредит: ' . $this->number1 . '<br>');
if ($this->type == 'active')
{
if($this->type1 == 'active')
{
$typeofinformation = '1';
}
}
if ($this->type == 'passive')
{
if($this->type1 == 'passive')
{
$typeofinformation = '2';
}
}
if ($this->type == 'active')
{
if($this->type1 == 'passive')
{
$typeofinformation = '3 или 4';
}
}
}
}
if (isset($_POST['type_1']) && isset($_POST['type_2']) && isset($_POST['number_1']) && isset($_POST['number_2']))
{
$bill = new Bill();
switch ($_POST['type_1'])
{
case '0':
$bill->type = 'passive';
break;
case '1':
$bill->type = 'active';
break;
}
switch ($_POST['type_2'])
{
case '0':
$bill->type1 = 'passive';
break;
case '1':
$bill->type1 = 'active';
break;
}
$bill->number = $_POST['number_1'];
$bill->number1 = $_POST['number_2'];
$bill->display();
echo('<hr>' . $bill->type . ' - ' . $bill->number . '<br>' . $bill->type1 . ' - ' . $bill->number1 . '<br>' . $typeofinformation . '<hr>');
}
?>
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