28.08.2008, 09:15
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Познавший АНТИЧАТ
Регистрация: 12.03.2008
Сообщений: 1,379
С нами:
9560486
Репутация:
1809
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Пример скипта загрузки файлов на сервер:
PHP код:
<?php
if ($HTTP_POST_VARS['submit'])
{
if (!is_uploaded_file($HTTP_POST_FILES['file']['tmp_name']))
{
$error = "You did not upload a file!";
unlink($HTTP_POST_FILES['file']['tmp_name']);
// assign error message, remove uploaded file, redisplay form.
}
else
{
//A file was uploaded
$maxfilesize=300000;
if ($HTTP_POST_FILES['file']['size'] > $maxfilesize)
{
$error = "File is too large.";
unlink($HTTP_POST_FILES['file']['tmp_name']);
// assign error message, remove uploaded file, redisplay form.
}
else
{
//File has passed all validation, copy it to the final destination and remove the
temporary file:
copy($HTTP_POST_FILES['file']['tmp_name'],$HTTP_POST_FILES['file']['name']);
unlink($HTTP_POST_FILES['file']['tmp_name']);
print "File has been successfully uploaded!";
exit;
}
}
}
?>
<html>
<head></head>
<body>
<form action="<?=$PHP_SELF?>" method="post" enctype="multipart/form-data">
<br><br>
Choose a file to upload:<br>
<input type="file" name="file"><br>
<input type="submit" name="submit" value="submit">
</form>
</body>
</html>
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