
16.12.2008, 06:33
|
|
Участник форума
Регистрация: 22.02.2007
Сообщений: 213
Провел на форуме: 388345
Репутация:
58
|
|
Из справочника
imagecopy
(PHP 4, PHP 5)
imagecopy — Copy part of an image
Description
bool imagecopy ( resource $dst_im , resource $src_im , int $dst_x , int $dst_y , int $src_x , int $src_y , int $src_w , int $src_h )
Copy a part of src_im onto dst_im starting at the x,y coordinates src_x , src_y with a width of src_w and a height of src_h . The portion defined will be copied onto the x,y coordinates, dst_x and dst_y .
Parameters
dst_im
Destination image link resource.
src_im
Source image link resource.
dst_x
x-coordinate of destination point.
dst_y
y-coordinate of destination point.
src_x
x-coordinate of source point.
src_y
y-coordinate of source point.
src_w
Source width.
src_h
Source height.
Return Values
Returns TRUE on success or FALSE on failure.
Examples
Example #1 Cropping the PHP.net logo
<?php
// Create image instances
$src = imagecreatefromgif('php.gif');
$dest = imagecreatetruecolor(80, 40);
// Copy
imagecopy($dest, $src, 0, 0, 20, 13, 80, 40);
// Output and free from memory
header('Content-Type: image/gif');
imagegif($dest);
imagedestroy($dest);
imagedestroy($src);
?>
l
|
|
|